Advertisements
Advertisements
प्रश्न
If one member of a pythagorean triplet is 2m, then the other two members are ______.
पर्याय
m, m2 + 1
m2 + 1, m2 – 1
m2, m2 – 1
m2, m + 1
Advertisements
उत्तर
If one member of a pythagorean triplet is 2m, then the other two members are m2 + 1, m2 – 1.
Explanation:
2m = 4
⇒ m = 2
m2 + 1 = 22 + 1
= 4 + 1
= 5
And m2 – 1 = 22 – 1
= 4 – 1
= 3
Now, 32 + 42 = 52
⇒ 9 + 16 = 25
⇒ 25 = 25
So 3, 4 and 5 are pythagorean triplets.
APPEARS IN
संबंधित प्रश्न
Find the square of the given number.
35
Write a Pythagorean triplet whose one member is 6.
Write a Pythagorean triplet whose one member is 14.
Observe the following pattern
22 − 12 = 2 + 1
32 − 22 = 3 + 2
42 − 32 = 4 + 3
52 − 42 = 5 + 4
and find the value of
992 − 962
Which of the following triplets are pythagorean?
(8, 15, 17)
Which of the following triplet pythagorean?
(14, 48, 51)
Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :
12 + 22 + 32 + 42 + ... + 102
Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication:
96
Find the square of the following number:
862
