Advertisements
Advertisements
प्रश्न
The hypotenuse of a right triangle with its legs of lengths 3x × 4x is ______.
पर्याय
5x
7x
16x
25x
Advertisements
उत्तर
The hypotenuse of a right triangle with its legs of lengths 3x × 4x is 5x.
Explanation:
Given, lengths of the legs of right angled triangle are 3x and 4x.
Now, hypotenuse = `sqrt((3x)^2 + (4x)^2)` ...[Using Pythagoras theorem]
= `sqrt(9x^2 + 16x^2)`
= `sqrt(25x^2)`
= 5x
APPEARS IN
संबंधित प्रश्न
Find the square of the given number.
32
What will be the units digit of the square of the following number?
977
What will be the units digit of the square of the following number?
53924
From the pattern, we can say that the sum of the first n positive odd numbers is equal to the square of the n-th positive number. Putting that into formula:
1 + 3 + 5 + 7 + ... n = n2, where the left hand side consists of n terms.
Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :
52 + 62 + 72 + 82 + 92 + 102 + 112 + 122
Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication:
54
Find the squares of the following numbers using diagonal method:
98
Find the square of the following number:
265
Write the Pythagorean triplet whose one of the numbers is 4.
A 5.5 m long ladder is leaned against a wall. The ladder reaches the wall to a height of 4.4 m. Find the distance between the wall and the foot of the ladder.
