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If Cos X = 4 5 and X is Acute, Find Tan 2x - Mathematics

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प्रश्न

 If \[\cos x = \frac{4}{5}\]  and x is acute, find tan 2

 

संख्यात्मक
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उत्तर

\[\cos x = \frac{4}{5}\]
\[\therefore \text{ sin } x = \sqrt{1 - \cos^2 x}\]
\[ = \sqrt{1 - \left( \frac{4}{5} \right)^2}\]
\[ = \sqrt{1 - \frac{16}{25}}\]
\[ = \sqrt{\frac{25 - 16}{25}}\]
\[ = \sqrt{\frac{9}{25}}\]
\[ = \frac{3}{5}\]
\[\therefore \tan x = \frac{\sin x}{\cos x}\]
\[ = \frac{\frac{3}{5}}{\frac{4}{5}}\]
\[ = \frac{3}{4}\]
Now,
\[\tan 2x = \frac{2 \text{ tan } x}{1 - \tan^2 x}\]
\[ = \frac{2\left( \frac{3}{4} \right)}{1 - \left( \frac{3}{4} \right)^2}\]
\[ = \frac{2\left( \frac{3}{4} \right)}{1 - \frac{9}{16}}\]
\[ = \frac{\frac{3}{2}}{\frac{7}{16}}\]
\[ = \frac{24}{7}\]
Hence, the value of tan 2x is \[\frac{24}{7}\] . 
 
 

 

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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पाठ 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.1 [पृष्ठ २९]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.1 | Q 30.2 | पृष्ठ २९

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