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If ЁЭЫ╝ and ЁЭЫ╜ be the zeroes of the polynomial `2x^2 - 7x + k` write the value of (ЁЭЫ╝ + ЁЭЫ╜ + ЁЭЫ╝ЁЭЫ╜).
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By using the relationship between the zeroes of the quadratic polynomial.
We have
Sum of zeroes = `(-("Coefficient of x"))/("Coefficient of "x^2)`
Product of zeroes =`("Constant term")/("Coefficient of "x^2)`
a = 2, b = −7, and c = k
∴ ∝+ β = `(-b)/c`
= `(-(-7))/2`
= `7/2`
∝β = `c/a`
= `k/2`
Now, ЁЭЫ╝ + ЁЭЫ╜ + ЁЭЫ╝ЁЭЫ╜ = `7/2 + k/2`
= `(7 + k)/2`
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