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If ЁЭЫ╝ and ЁЭЫ╜ be the zeroes of the polynomial 2тБвЁЭСе2 тИТ7тБвЁЭСе +ЁЭСШ write the value of (ЁЭЫ╝ + ЁЭЫ╜ + ЁЭЫ╝ЁЭЫ╜).

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If ЁЭЫ╝ and ЁЭЫ╜ be the zeroes of the polynomial `2x^2 - 7x + k` write the value of (ЁЭЫ╝ + ЁЭЫ╜ + ЁЭЫ╝ЁЭЫ╜).

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By using the relationship between the zeroes of the quadratic polynomial.
We have  

Sum of zeroes = `(-("Coefficient of x"))/("Coefficient of "x^2)` 

Product of zeroes =`("Constant term")/("Coefficient of "x^2)` 

a = 2, b = −7, and c = k

∴ ∝+ β = `(-b)/c`

= `(-(-7))/2`

= `7/2`

∝β = `c/a`

= `k/2` 

Now, ЁЭЫ╝ + ЁЭЫ╜ + ЁЭЫ╝ЁЭЫ╜ = `7/2 + k/2`

= `(7 + k)/2`

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