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If µ and σ2 are the mean and variance of the discrete random variable X and E(X + 3) = 10 and E(X + 3)2 = 116, find µ and σ2 - Mathematics

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प्रश्न

If µ and σ2 are the mean and variance of the discrete random variable X and E(X + 3) = 10 and E(X + 3)2 = 116, find µ and σ

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उत्तर

Given E(X + 3) = 10

E(aX + b) = aE(X) + b

E(X + 3) = 10

⇒ E(X) + 3 = 10

⇒ µ = E(X) = 7

E(X + 3)2 = 116

E(X2 + 6X + 9) = 116

E(X2) + 6E(X) + 9 = 116

E(X2) + 6(7) + 9 = 116

E(X2) = 65

σ² = Var (X)

= E(X2) – [E(X)]2

= 65 – 49

= 16

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Mathematical Expectation
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पाठ 11: Probability Distributions - Exercise 11.4 [पृष्ठ २१०]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 11 Probability Distributions
Exercise 11.4 | Q 3 | पृष्ठ २१०

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