मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी वाणिज्य इयत्ता १२

What is the expected value of a game that works as follows: I flip a coin and if tails pay you ₹ 2; if heads pay you ₹ 1. In either case, I also pay you ₹ 50 - Business Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

What is the expected value of a game that works as follows: I flip a coin and if tails pay you ₹ 2; if heads pay you ₹ 1. In either case, I also pay you ₹ 0.50

तक्ता
बेरीज
Advertisements

उत्तर

Let x be the remain variable denoting the amount paying for a game of flip coin then x and takes 2 and 1

P(X = 2) = `1/2` (getting a head)

P(X = 1) = `1/2` (getting a tail)

Hence the probability of X is

X 2 1
P(X = x) `1/2` `1/2`

Expected value E(X) = `sum_x "P"(x)`

= `(2)(1/2) + 1(1/2)`

= `1 + 1/2`

= `3/2`

Since I pay you ₹ 50 in either case

E(X) = 50 × `3/2` = ₹ 75

shaalaa.com
Mathematical Expectation
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Random Variable and Mathematical expectation - Miscellaneous problems [पृष्ठ १४४]

APPEARS IN

सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
पाठ 6 Random Variable and Mathematical expectation
Miscellaneous problems | Q 7 | पृष्ठ १४४

संबंधित प्रश्‍न

For the random variable X with the given probability mass function as below, find the mean and variance.

`f(x) = {{:(2(x - 1), 1 < x ≤ 2),(0, "otherwise"):}`


Choose the correct alternative:

A random variable X has binomial distribution with n = 25 and p = 0.8 then standard deviation of X is


Choose the correct alternative:

Four buses carrying 160 students from the same school arrive at a football stadium. The buses carry, respectively, 42, 36, 34, and 48 students. One of the students is randomly selected. Let X denote the number of students that were on the bus carrying the randomly selected student. One of the 4 bus drivers is also randomly selected. Let Y denote the number of students on that bus. Then E(X) and E(Y) respectively are


Choose the correct alternative:

On a multiple-choice exam with 3 possible destructive for each of the 5 questions, the probability that a student will get 4 or more correct answers just by guessing is


Choose the correct alternative:

If P(X = 0) = 1 – P(X = 1). If E[X] = 3 Var(X), then P(X = 0) is


Choose the correct alternative:

If X is a binomial random variable with I expected value 6 and variance 2.4, Then P(X = 5) is


State the definition of Mathematical expectation using continuous random variable


Choose the correct alternative:

Demand of products per day for three days are 21, 19, 22 units and their respective probabilities are 0.29, 0.40, 0.35. Profit per unit is 0.50 paisa then expected profits for three days are


Choose the correct alternative:

Given E(X) = 5 and E(Y) = – 2, then E(X – Y) is


Choose the correct alternative: 

A listing of all the outcomes of an experiment and the probability associated with each outcome is called


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×