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Two balls are drawn in succession without replacement from an urn containing four red balls and three black balls. Let X be the possible outcomes drawing red balls. Find the probability mass

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प्रश्न

Two balls are drawn in succession without replacement from an urn containing four red balls and three black balls. Let X be the possible outcomes drawing red balls. Find the probability mass function and mean for X

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उत्तर

Let X be the random variable that denotes the number of red balls.

X = {0, 1, 2}

Sample space consist of 7C2 = 21

X= 0, X-1 (BB) = 3C2

X= 1, X-1 (BR) = 3C1 × 4C1 = 12

X = 2, X-1 (RR) 4C2 = 6

Values of random variable 0 1 2 Total
Number of elements in inverse image 3 12 6 21

Probability mass function

x 0 1 2
F(x) `3/21` `12/21` `6/21`

Mean: `mu = "E"("X")`

= `sum x f(x)`

= `0 xx 3/21 + 1 xx 12/21 + 2 xx 6/21`

= `24/21`

= `8/7`

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पाठ 11: Probability Distributions - Exercise 11.4 [पृष्ठ २१०]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 11 Probability Distributions
Exercise 11.4 | Q 2 | पृष्ठ २१०

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