Question

If 550 μA is flowing through 10 kΩ of resistance, what is the voltage drop across the resistor?

Answer 1

Given Data:

Current (I) = 550 μA = 550 × 10⁻⁶ A

Resistance (R) = 10 kΩ = 10 × 10³ Ω = 10,000 Ω

Formula:

According to Ohm’s Law, the voltage drop (V) across a resistor is given by:

V = I × R

= (550 × 10⁻⁶ A) × (10 × 10³ Ω)

= 550 × 10 × 10⁻⁶⁺³

= 5500 × 10⁻³

= `5500/1000`

= 5.5 V

The voltage drop across the resistor is 5.5 Volts.