Advertisements
Advertisements
प्रश्न
If 2x = 4y = 8z and `1/(2x) + 1/(4y) + 1/(8z) = 4` , find the value of x.
Advertisements
उत्तर
2x = 4y = 8z and `1/(2x) + 1/(4y) + 1/(8z) = 4`
2x = 4y = 8z
⇒ 2x = 22y = 23z
⇒ x = 2y = 3z
⇒ y = `x/2 and z = x/3`
Now, `1/(2x) + 1/(4y) + 1/(8z) = 4`
⇒ `1/(2x) + 1/[(4x)/2] + 1/[(8x)/3] = 4`
⇒ `1/(2x) + 2/(4x) + 3/(8x) = 4`
⇒ `1/(2x) + 1/(2x) + 3/(8x) = 4`
⇒ `[ 4 + 4 + 3 ]/(8x) = 4`
⇒ `11/(8x) = 4`
⇒ x = `11/32`.
APPEARS IN
संबंधित प्रश्न
Find x, if : `( sqrt(3/5))^( x + 1) = 125/27`
Solve : 4x - 2 - 2x + 1 = 0
Evaluate the following:
`(4^3 xx 3^7 xx 5^6)/(5^8 xx 2^7 xx 3^3)`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
1 = px
Solve for x:
22x- 1 − 9 x 2x − 2 + 1 = 0
Solve for x:
`sqrt((3/5)^(x + 3)) = (27^-1)/(125^-1)`
Solve for x:
9x+4 = 32 x (27)x+1
Find the value of 'a' and 'b' if:
`(sqrt243)^"a" ÷ 3^("b" + 1)` = 1 and `27^"b" - 81^(4 -"a"/2)` = 0
Prove the following:
`sqrt(x^-1 y) · sqrt(y^-1 z) · sqrt(z^-1 x)` = 1
