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If | → a | = 2 , ∣ ∣ → B ∣ ∣ = 5 and ∣ ∣ → a × → B ∣ ∣ = 8 , Find → a ⋅ → B . - Mathematics

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प्रश्न

\[\text{ If }  \left| \vec{a} \right| = 2, \left| \vec{b} \right| = 5 \text{ and }  \left| \vec{a} \times \vec{b} \right| = 8, \text { find }  \vec{a} \cdot \vec{b} .\]

 

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उत्तर

\[\text{ We know } \]
\[ \left( \vec{a} . \vec{b} \right)^2 + \left| \vec{a} \times \vec{b} \right|^2 = \left| \vec{a} \right|^2 \left| \vec{b} \right|^2 \]
\[ \Rightarrow \left( \vec{a} . \vec{b} \right)^2 + 8^2 = 2^2 \times 5^2 ( \because \left| \vec{a} \times \vec{b} \right| = 8, \left| \vec{a} \right| = 2 \text{ and }  \left| \vec{b} \right| = 5)\]
\[ \Rightarrow \left( \vec{a} . \vec{b} \right)^2 + 64 = 100\]
\[ \Rightarrow \left( \vec{a} . \vec{b} \right)^2 = 36\]
\[ \Rightarrow \left( \vec{a} . \vec{b} \right) = 6\]

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पाठ 25: Vector or Cross Product - Exercise 25.1 [पृष्ठ ३०]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 25 Vector or Cross Product
Exercise 25.1 | Q 11 | पृष्ठ ३०

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