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If 18% of the bolts produced by a machine are defective, determine the probability that out of the 4 bolts chosen at random atmost 2 will be defective

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प्रश्न

If 18% of the bolts produced by a machine are defective, determine the probability that out of the 4 bolts chosen at random atmost 2 will be defective

बेरीज
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उत्तर

p(almost 2 will be defective) = p(x ≤ 2)

= p(x = 0) + (p(x = 1) + p(x = 2)

= 4C0(0.18)°(0.82)4-0 + 4C1(0.18)1(0.82)4-1 + 4C2 (0.18)2 (0.82)4-2 

= (0.82)4 + 4 × (0.18) × (0.82)3 + `(4 xx 3)/(1 xx 2)` × (0.18)2 (0.82)2

= 0.45212176 + (0.72 × 0.551368) + (6 × 0.0324 × 0.6724)

= 0.45212176 + 0.39698496 + 013071456

= 0.97982128

= 0.9798

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पाठ 7: Probability Distributions - Exercise 7.1 [पृष्ठ १५५]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
पाठ 7 Probability Distributions
Exercise 7.1 | Q 10. (iii) | पृष्ठ १५५

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