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प्रश्न
How the following conversion can be carried out?
Isopropyl alcohol to iodoform
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उत्तर
\[\begin{array}{cc}
\ce{CH3 - CH - CH3 + 4I2 + 6NaOH ->[\Delta][Iodoform Reaction] \underset{Iodoform}{CHI3} + CH3COONa + 5NaI + 5H2O}\\
|\phantom{........................................................................}\\
\ce{\underset{Isopropylalcohol}{OH}}\phantom{......................................................................}
\end{array}\]
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