Advertisements
Advertisements
प्रश्न
How much is the angular momentum of an electron when it is orbiting in the second Bohr orbit of hydrogen atom?
Advertisements
उत्तर
L = `"nh"/(2pi) = "2h"/(2pi) = "h"/pi`
APPEARS IN
संबंधित प्रश्न
Using Bohr’s postulates, obtain the expression for total energy of the electron in the nth orbit of hydrogen atom.
The difference in the frequencies of series limit of Lyman series and Balmer series is equal to the frequency of the first line of the Lyman series. Explain.
A beam of monochromatic light of wavelength λ ejects photoelectrons from a cesium surface (Φ = 1.9 eV). These photoelectrons are made to collide with hydrogen atoms in ground state. Find the maximum value of λ for which (a) hydrogen atoms may be ionized, (b) hydrogen atoms may get excited from the ground state to the first excited state and (c) the excited hydrogen atoms may emit visible light.
Consider a neutron and an electron bound to each other due to gravitational force. Assuming Bohr's quantization rule for angular momentum to be valid in this case, derive an expression for the energy of the neutron-electron system.
Answer the following question.
Calculate the orbital period of the electron in the first excited state of the hydrogen atom.
What is the energy in joules released when an electron moves from n = 2 to n = 1 level in a hydrogen atom?
When an electric discharge is passed through hydrogen gas, the hydrogen molecules dissociate to produce excited hydrogen atoms. These excited atoms emit electromagnetic radiation of discrete frequencies which can be given by the general formula
`bar(v) = 109677 1/n_1^2 - 1/n_f^2`
What points of Bohr’s model of an atom can be used to arrive at this formula? Based on these points derive the above formula giving description of each step and each term.
Taking the Bohr radius as a0 = 53 pm, the radius of Li++ ion in its ground state, on the basis of Bohr’s model, will be about ______.
The first ionization energy of H is 21.79 × 10-19 J. The second ionization energy of He atom is ______ × 10-19J.
Calculate the shortest wavenumber in hydrogen spectrum of Lyman series. (RH = 109677 cm−1)
