Advertisements
Advertisements
प्रश्न
How does the angle of deviation produced by a prism change with increase in the angle of incidence. Draw a curve showing the variation in the angle of deviation with the angle of incidence at a prism surface.
Advertisements
उत्तर १
As the angle of incidence increases, the angle of deviation decreases first and reaches to a minimum value (δm) for a certain angle of incidence. By further increasing the angle of incidence, the angle of deviation is found to increase.
Variation of angle of deviation (δ) with angle of incidence(i):
उत्तर २
The deviation angle first increases with increasing incidence angle and then decreases. From figure,
δ = δ1 + δ2 ....(i)
and i = δ1 +γ1 ; e = δ2 +γ2
⇒ i = γ1 = δ1 ....(ii)
⇒ e - γ1 = δ2 ....(iii)
from ΔON1 N2
γ1 +γ2 + ∠N1 ON2=180° ....(iv)
from cyclic quadrilateral
∠A + ∠N1ON2 = 180° ....(v)
from (iv) and (v)
γ1 +γ2 = A
δ = i - γ1 + e - γ2
=( i - e) - (γ1 + γ2) ...(vi)
at δm ;
i = e ; γ1 = γ2= γ
δm =2i - A ...(vii)

The variation in the angle of deviation with the angle of incidence at a prism surface

Graph between i and δm
APPEARS IN
संबंधित प्रश्न
A student very cautiously traces the path of a ray through a glass slab for different values of the angle of incidence (∠i). He then measures the corresponding values of the angle of refraction (∠r) and the angle of emergence (∠e) for every value of the angle of incidence. On analysing these measurements of angles, his conclusion would be
(A) ∠i > ∠r > ∠e
(B) ∠i = ∠e > ∠r
(C) ∠i < ∠r < ∠e
(D) ∠i = ∠e < ∠r
Draw the diagram of refraction of light in the glass slab
A ray of light of wavelength 6600 Å suffer refraction from air to glass. Taking \[\ce{_a\mu_g = \frac{3}{2}}\], find the wavelength of light in glass.
After tracing the path of rays of light through a glass slab for three different angles of incidence, a student measured the corresponding values angle of refraction r and angle of emergence e and recorded them in the table given below:
|
S. No. |
∠i |
∠i |
∠e |
|
I |
30° |
20° |
31° |
|
II |
40° |
25° |
40° |
|
III |
50° |
31° |
49° |
The correct observations are:
(A) I and II
(B) II and III
(C) I and III
(D) I, II and III
A ray of light falls normally on the surface of a transparent glass slab. Draw a ray diagram to show its path and also mark angle of incidence and angle of emergence.
Glass is transparent in nature. Why does glass powder look opaque? When water is poured over it, it again becomes transparent. Why?
Does the depth of a tank of water appear to change or remain the same when viewed normally from above?
A glass slab is placed over a page on which the word VIBGYOR is printed with each letter in its corresponding colour.
- Will the image of all the letters be in the same place?
- If not, the state which letter will be raised to the maximum. Give a reason for your answer.
Comment on the statement ‘The refractive index of glass is 3/2.’
In the diagram below, PQ is a ray of light incident on a rectangular glass block.

Copy the diagram and complete the path of the ray of light through the glass block. In your diagram, mark the angle of incidence by letter ‘i’ and the angle of emergence by the letter ‘e’.
