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प्रश्न
Give the empirical formula of C6H18O3
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उत्तर
C6H18O3
Explanation:
Molecular formula = C6H18O3
Take the common multiple
Molecular formula = (C2H6O)3
Molecular Formula = (Empirical formula)n
Thus, the empirical formula = C2H6O
संबंधित प्रश्न
Explain the terms empirical formula and molecular formula.
Give the empirical formula of C6H6.
Give the empirical formula of C2H2
A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.
Determine the empirical formula of a compound containing 47.9‰ K, 5.5‰ beryllium and 46.6‰ fluorine by mass.
A compound 'X' consists of 4.8% of C and 95.2% of Br by mass.
Determine the empirical formula of this compound.
[C = 12, Br = 80]
A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.
Explain the term empirical formula.
A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correctly to 1 decimal place. (H = 1; \[\ce{C}\] = 12; \[\ce{Cl}\] = 35.5)
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