Advertisements
Advertisements
प्रश्न
Give the empirical formula of C6H18O3.
Molecular formula of a compound is C6H18O3. Find its empirical formula.
Advertisements
उत्तर
Molecular formula = C6H18O3
Take the common multiple,
Molecular formula = (C2H6O)3
Molecular Formula = (Empirical formula)n
Thus, the empirical formula = C2H6O
संबंधित प्रश्न
Find the empirical formula and the molecular formula of an organic compound from the data given below :
C = 75.92%, H = 6.32% and N = 17.76%
The vapour density of the compound is 39.5.
[C = 12, H = 1, N = 14]
Give the empirical formula of CH3COOH
Give example of compound whose:
Empirical formula is the same as the molecular formula.
Give example of compound whose:
Empirical formula is different from the molecular formula.
Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
The percentage composition of sodium phosphate, as determined by analysis is : 42.1% Na, 18.9% P, 39% of O. Find the empirical formula of the compound.
[H =1, N =14, Na = 23, P = 31, Cl = 35.5, Pt = 195]
Find the percentage of mass water in Epsom salt MgSO4.7H2O.
A compound is formed by 24 g of X and 64 g of oxygen. If the atomic mass of X = 12 and O = 16, calculate the simplest formula of the compound.
- A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correctly to 1 decimal place. (H = 1; C = 12; Cl = 35.5)
- The relative molecular mass of this compound is 168, so what is its molecular formula?
- By what type of reaction could this compound be obtained from ethyne?
A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. By what type of reaction could this compound be obtained from ethylene?
