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प्रश्न
Give the empirical formula of C6H18O3
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उत्तर
C6H18O3
Explanation:
Molecular formula = C6H18O3
Take the common multiple
Molecular formula = (C2H6O)3
Molecular Formula = (Empirical formula)n
Thus, the empirical formula = C2H6O
संबंधित प्रश्न
If the empirical formula of a compound is CH and it has a vapor density of 13, find the molecular formula of the compound.
Consider the following reaction and based on the reaction answer the questions that follow:
Calculate:
1) the quantity in moles of (NH4)2Cr2O7 if 63gm of(NH4)2Cr2O7 is heated.
2) the quantity in moles of nitrogen formed.
3) the volume in liters or dm3 of N2 evolved at S.T.P.
4) the mass in grams of Cr2O3 formed at the same time
(Atomic masses: H=1, Cr= 52, N=14]
Explain the terms empirical formula and molecular formula.
A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.
Determine the empirical formula of a compound containing 47.9‰ K, 5.5‰ beryllium and 46.6‰ fluorine by mass.
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Determine the empirical formula of this compound.
[C = 12, Br = 80]
A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.
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In a compound of magnesium (Mg = 24) and nitrogen (N = 14), 18 g of magnesium combines with 7g of nitrogen.
Deduce the simplest formula by answering the following questions:
- How many gram-atoms of magnesium are equal to 18g?
- How many gram-atoms of nitrogen are equal to 7g of nitrogen?
- Calculate the simple ratio of gram-atoms of magnesium to gram-atoms of nitrogen and hence the simplest formula of the compound formed.
The Empirical formula of an organic compound is CHCl2.
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