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प्रश्न
Give one example of the reaction where order and molecularity are the same.
Mention any two factors that influence the rate of chemical reaction.
If for the reaction A → products, a straight line graph passing through origin is obtained between the rate of reaction against concentration of A, what would be the order of reaction? Why?
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उत्तर
- \[\ce{2NO_{2(g)} -> 2NO_{2(g)} + O_{2(g)}}\]
The order of a reaction is 2 and its molecularity is also 2. - Temperature, use of catalyst
- The reaction would be first order.
The differential rate law for the first-order reaction A → products is
The equation is of the form y = mx + c. A plot of rate versus [A]t is a straight line passing through the origin. The slope of straight line = k.
Variation of rate with [A]
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Identify the molecularity of following elementary reaction:
NO(g) + O3(g) → NO3(g) + O(g)
The reaction takes place in two steps as
(i) \[\ce{NO2Cl(g) ->[k1] NO2(g) + Cl(g)}\]
(ii) \[\ce{NO2Cl(g) + Cl(g) ->[k2] NO2(g) + Cl2(g)}\]
Identify the reaction intermediate.
What is an elementary reaction?
How does a catalyst differ from reaction intermediate?
Find out the reaction intermediate and molecularity of the following reactions.
\[\ce{NO_{(g)} + Cl2_{(g)} -> NOCl_{2(g)}}\]
\[\ce{NOCl_{2(g)} + NO_{(g)} -> 2NOCl_{(g)}}\]
Draw the structure of BrF5 and HOCl.
A complex chemical reaction takes place in two steps.
Step I: NO(g) + O3(g) → NO3(g) + O(g)
Step II: NO3(g) + O(g) → NO2(g) + O2(g)
The predicted rate law is rate = k[NO][O3]
- Identify the rate determining step.
- Name the reaction intermediate/s. Why is/are it/these intermediate/s?
Define molecularity of reaction.
