मराठी

For any prism, obtain a relation between the angle of the prism (A), the angle of minimum deviation (δm) and the refractive index of its material (μ or n).

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प्रश्न

For any prism, obtain a relation between the angle of the prism (A), the angle of minimum deviation (δm) and the refractive index of its material (μ or n).

संख्यात्मक
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उत्तर

In the given diagram,

OP is the incident ray, which makes the angle i, with normal, and QR is the angle of emergence, which is represented by i2. A is the prism angle, and it is the refractive index of the prism.

Now, we know that,

A = Prism angle, δ = Angle of deviation

i1 = Angle of incidence

i2 = Angle of emergent

In the case of minimum deviation

∠r1 = ∠r2 = ∠r

A = ∠r1 + ∠r2 = ∠2r

`=> ∠"r" = "A"/2`

Now again

A + δ = i1 + i2    ...(∵ In the case of minimum deviation)

i1 = i2 = i and δ = δm

So, A + δm = i + i = 2i

Now, `angle "i" = ("A" + delta_"m")/2`

For Snell's law:

`mu = (sin i)/(sin r)`

`=> mu = (sin  ("A" + delta_m)/2)/(sin  "A"/2)`

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