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प्रश्न
Find x.
23x = 82x + 1
बेरीज
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उत्तर
We have, 23x = 82x + 1
⇒ 23x = (23)2x + 1
⇒ 23x = (2)6x + 3 ...[∵ (am)n = (a)m × n]
On comparing the power of 2, we get
3x = 6x + 3
⇒ –3 = 3x
⇒ x = –1
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पाठ 8: Exponents and Powers - Exercise [पृष्ठ २७४]
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संबंधित प्रश्न
The value of 35 ÷ 3–6 is ______.
The value of (–2)2×3 – 1 is ______.
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`[(2/13)^-6 ÷ (2/13)^3]^3 xx (2/13)^-9` = ______.
On dividing 85 by ______ we get 8.
Solve the following:
`(1/2)^-2 ÷ (1/2)^-3`
Supply the missing information for diagram.
Find x.
2x + 2x + 2x = 192
Find x.
5x + 5x – 1 = 750
Simplify:
`(4/13)^4 xx (13/7)^2 xx (7/4)^3`
