Advertisements
Advertisements
प्रश्न
Find the volume in cubic metre (cu. m) of the cuboid whose dimensions is length = 10 m, breadth = 25 dm, height = 50 cm.
Advertisements
उत्तर
Length = 10 m
Breadth = 25 dm
\[ = \frac{25}{10}m ( \because 10 dm = 1m)\]
\[ = 2 . 5 m\]
\[\text { Height } = 25 cm = \frac{25}{100}m = 0 . 25 m\]
\[ \therefore\text { Volume of the cuboid = length } \times \text { breadth } \times\text { height }\]
\[ = 10 \times 2 . 5 \times 0 . 25\]
\[ = 6 . 25 m^3\]
APPEARS IN
संबंधित प्रश्न
Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4 m × 3 m?
There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?
![]() |
![]() |
| (a) | (b) |
The length of a hall is 18 m and the width 12 m. The sum of the areas of the floor and the
flat roof is equal to the sum of the areas of the four walls. Find the height of the hall.
The weight of a metal block of size 5 cm by 4 cm by 3 cm is 1 kg. Find the weight of a block of the same metal of size 15 cm by 8 cm by 3 cm.
Find the surface area of a cuboid whose length = 10 cm, breadth = 12 cm, height = 14 cm.
If V is the volume of a cuboid of dimensions a, b, c and S is its surface area, then prove that \[\frac{1}{V} = \frac{2}{S}\left( \frac{1}{a} + \frac{1}{b} + \frac{1}{c} \right)\]
A cuboid has total surface area of 372 cm2 and its lateral surface area is 180 cm2, find the area of its base.
Three equal cubes of sides 5cm each are placed to form a cuboid. Find the volume and the total surface area of the cuboid.
The surface area of a cuboid formed by joining two cubes of side a face to face is ______.


