मराठी

Find the values of x, y if the distances of the point (x, y) from (-3, 0) as well as from (3, 0) are 4. - Mathematics

Advertisements
Advertisements

प्रश्न

Find the values of x, y if the distances of the point (x, y) from (-3, 0)  as well as from (3, 0) are 4.

बेरीज
Advertisements

उत्तर

We have P(x, y), Q(-3, 0) and R(3, 0)

`PQ = sqrt((x + 3)^2 + (y - 0)^2)`

`=> 4 = sqrt(x^2 + 9 + 6x + y^2)`

Squaring both sides

`=> (4)^2 = (sqrt(x^2 + 9 + 6x + y^2))`

`=> 16 = x^2 + 9 + 6x + y^2`

`=> x^2 + y^2 = 16 - 9 - 6x`

`=> x^2 + y^2 = 7 -  6x`   ......(1)

`PR = (sqrt((x - 3)^2 + (y - 0)^2)`

`=> 4 = sqrt(x^2 + 9 - 6x + y^2)`

Squaring both sides

`(4)^2 = (sqrt(x^2 + 9 - 6x + y^2))`

`=> 16 = x^2 + 9 - 6x + y^2`

`=> x^2 + y^2  = 16 - 9 + 6x`

`=> x^2 + y^2 = 7 + 6x`  .....(2)

Equating (1) and (2)

7 - 6x = 7 + 6x

⇒ 7 - 7 = 6x + 6x

⇒ 0 = 12x

⇒ x = 0

Substituting the value of x = 0 in (2)

`x^2 + y^2 = 7 + 6x`

`0 + y^2 = 7 + 6 xx 0`

`y^2 = 7`

`y = +- sqrt7`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Co-Ordinate Geometry - Exercise 6.2 [पृष्ठ १५]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
पाठ 6 Co-Ordinate Geometry
Exercise 6.2 | Q 4 | पृष्ठ १५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

If P and Q are two points whose coordinates are (at2 ,2at) and (a/t2 , 2a/t) respectively and S is the point (a, 0). Show that `\frac{1}{SP}+\frac{1}{SQ}` is independent of t.


Find the coordinates of the centre of the circle passing through the points (0, 0), (–2, 1) and (–3, 2). Also, find its radius.


ABC is a triangle and G(4, 3) is the centroid of the triangle. If A = (1, 3), B = (4, b) and C = (a, 1), find ‘a’ and ‘b’. Find the length of side BC.


Find the distance between the following pair of points:

 (a+b, b+c) and (a-b, c-b)


If the point P(x, y ) is equidistant from the points A(5, 1) and B (1, 5), prove that x = y.


Using the distance formula, show that the given points are collinear:

(-2, 5), (0,1) and (2, -3)


Find the distance between the following pair of point.

 P(–5, 7), Q(–1, 3)


Find the distance between the following pair of point.

T(–3, 6), R(9, –10)


Find the distances between the following point.
A(a, 0), B(0, a)


Find the distances between the following point.

P(–6, –3), Q(–1, 9) 


Find the distance of a point (7 , 5) from another point on the x - axis whose abscissa is -5.


Find the coordinate of O , the centre of a circle passing through A (8 , 12) , B (11 , 3), and C (0 , 14). Also , find its radius.


The length of line PQ is 10 units and the co-ordinates of P are (2, -3); calculate the co-ordinates of point Q, if its abscissa is 10.


Show that each of the triangles whose vertices are given below are isosceles :
(i) (8, 2), (5,-3) and (0,0)
(ii) (0,6), (-5, 3) and (3,1).


Show that the quadrilateral with vertices (3, 2), (0, 5), (- 3, 2) and (0, -1) is a square.


The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x ______


Show that the points (0, –1), (8, 3), (6, 7) and (– 2, 3) are vertices of a rectangle.


The distance between the points A(0, 6) and B(0, -2) is ______.


Case Study -2

A hockey field is the playing surface for the game of hockey. Historically, the game was played on natural turf (grass) but nowadays it is predominantly played on an artificial turf.

It is rectangular in shape - 100 yards by 60 yards. Goals consist of two upright posts placed equidistant from the centre of the backline, joined at the top by a horizontal crossbar. The inner edges of the posts must be 3.66 metres (4 yards) apart, and the lower edge of the crossbar must be 2.14 metres (7 feet) above the ground.

Each team plays with 11 players on the field during the game including the goalie. Positions you might play include -

  • Forward: As shown by players A, B, C and D.
  • Midfielders: As shown by players E, F and G.
  • Fullbacks: As shown by players H, I and J.
  • Goalie: As shown by player K.

Using the picture of a hockey field below, answer the questions that follow:

The coordinates of the centroid of ΔEHJ are ______.


Find distance between points P(– 5, – 7) and Q(0, 3).

By distance formula,

PQ = `sqrt(square + (y_2 - y_1)^2`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(125)`

= `5sqrt(5)`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×