Advertisements
Advertisements
प्रश्न
The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x = ______.
पर्याय
2
6
3
1
Advertisements
उत्तर
The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x = 6.
Explanation:
Let P(x1, y1) = P(2, 2) and Q(x2, y2) = Q(5, x)
Here, x1 = 2, y1 = 2, x2 = 5, y2 = x
By distance formula,
d(P, Q) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)`
∴ `5 = sqrt((5 - 2)^2 + (x - 2)^2)`
∴ `5 = sqrt(9 + x^2 - 4x + 4)`
∴ 52 = x2 – 4x + 13 ...[Squaring both sides]
∴ 25 = x2 – 4x + 13
∴ x2 – 4x + 13 – 25 = 0
∴ x2 – 4x – 12 = 0
∴ (x – 6) (x + 2) = 0
∴ x – 6 = 0 or x + 2 = 0
∴ x = 6 or x = –2
APPEARS IN
संबंधित प्रश्न
Show that the points (a, a), (–a, –a) and (– √3 a, √3 a) are the vertices of an equilateral triangle. Also find its area.
If the opposite vertices of a square are (1, – 1) and (3, 4), find the coordinates of the remaining angular points.
Check whether (5, -2), (6, 4) and (7, -2) are the vertices of an isosceles triangle.
Find the distance between the following pair of points:
(asinα, −bcosα) and (−acos α, bsin α)
Show that the quadrilateral whose vertices are (2, −1), (3, 4) (−2, 3) and (−3,−2) is a rhombus.
Find the distance between the points
(ii) A(7,-4)and B(-5,1)
Find the distance between the points
A(1,-3) and B(4,-6)
Find value of x for which the distance between the points P(x,4) and Q(9,10) is 10 units.
Find the distances between the following point.
P(–6, –3), Q(–1, 9)
The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is ______.
Find the relation between a and b if the point P(a ,b) is equidistant from A (6,-1) and B (5 , 8).
Find the coordinates of O, the centre passing through A( -2, -3), B(-1, 0) and C(7, 6). Also, find its radius.
Prove that the points (1 ,1),(-4 , 4) and (4 , 6) are the certices of an isosceles triangle.
Find the distance between the points (a, b) and (−a, −b).
The distance between the points (3, 1) and (0, x) is 5. Find x.
Given A = (3, 1) and B = (0, y - 1). Find y if AB = 5.
If the point (x, y) is at equidistant from the point (a + b, b – a) and (a-b, a + b). Prove that ay = bx.
The distance of the point P(–6, 8) from the origin is ______.
|
Case Study Trigonometry in the form of triangulation forms the basis of navigation, whether it is by land, sea or air. GPS a radio navigation system helps to locate our position on earth with the help of satellites. |
- Make a labelled figure on the basis of the given information and calculate the distance of the boat from the foot of the observation tower.
- After 10 minutes, the guard observed that the boat was approaching the tower and its distance from tower is reduced by 240(`sqrt(3)` - 1) m. He immediately raised the alarm. What was the new angle of depression of the boat from the top of the observation tower?

