मराठी

Find the values of k for the following quadratic equation, so that they have two equal roots. kx (x - 2) + 6 = 0 - Mathematics

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प्रश्न

Find the values of k for the following quadratic equation, so that they have two equal roots.

kx (x - 2) + 6 = 0

बेरीज
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उत्तर

kx(x - 2) + 6 = 0

or kx2 - 2kx + 6 = 0

Comparing this equation with ax2 + bx + c = 0, we get

a = k, b = - 2k and c = 6

Discriminant = b2 - 4ac

= (-2k)2 - 4 (k) (6)

= 4k2 - 24k

k2 - 6k = 0

 k (k - 6) = 0

For equal roots,

b2 - 4ac = 0

4k2 - 24k = 0

4k (k - 6) = 0

Either 4k = 0 or k = 6 = 0

k = 0 or k = 6

However, if k = 0, then the equation will not have the terms 'x2' and 'x'.

Therefore, if this equation has two equal roots, k should be 6 only.

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पाठ 4: Quadratic Equations - Exercise 4.4 [पृष्ठ ९१]

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एनसीईआरटी Mathematics [English] Class 10
पाठ 4 Quadratic Equations
Exercise 4.4 | Q 2.2 | पृष्ठ ९१

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