Advertisements
Advertisements
प्रश्न
Find the discriminant of the following equations and hence find the nature of roots: 16x2 - 40x + 25 = 0
Advertisements
उत्तर
16x2 - 40x + 25 = 0
a = 16, b = -40, c = 25
∴ D = b2 - 4ac
= (-40)2 - 4 x 16 x 25
= 1600 - 1600
= 0
∴ Discriminant = 0
∵ D = 0
∴ Roots are real and equal.
APPEARS IN
संबंधित प्रश्न
Find the values of k for which the roots are real and equal in each of the following equation:
x2 - 2kx + 7k - 12 = 0
Determine the nature of the roots of the following quadratic equation :
x2 -5x+ 7= 0
Find, using the quadratic formula, the roots of the following quadratic equations, if they exist
3x2 – 5x + 2 = 0
Determine, if 3 is a root of the given equation
`sqrt(x^2 - 4x + 3) + sqrt(x^2 - 9) = sqrt(4x^2 - 14x + 16)`.
`(2)/x^2 - (5)/x + 2` = 0
Discuss the nature of the roots of the following quadratic equations : -2x2 + x + 1 = 0
Find the value(s) of k for which each of the following quadratic equation has equal roots: 3kx2 = 4(kx – 1)
If –5 is a root of the quadratic equation 2x2 + px – 15 = 0, then:
Every quadratic equation has at least two roots.
The roots of quadratic equation x(x + 8) + 12 = 0 are ______.
