Advertisements
Advertisements
प्रश्न
In each of the following, determine whether the given numbers are roots of the given equations or not; 6x2 – x – 2 = 0; `(-1)/(2), (2)/(3)`
Advertisements
उत्तर
6x2 – x – 2 = 0; `(-1)/(2), (2)/(3)`
If x = `(-1)/(2)`, then
= `6(-1/2)^2 - (-1/2) - 2`
= `6 xx (1)/(4) + (1)/(2) - 2`
= `(3)/(2) + (1)/(2) - 2`
= `(4)/(2) - 2` = 0
∴ x = `(-1)/(2)` is its root
If x = `(2)/(3)`, then
= `6 xx (4)/(9) - (2)/(3) - 2`
= `(8)/(3) - (2)/(3) - 2`
= `(6)/(3) - 2` = 0
∴ x = `(2)/(3)` is also its root.
Hence `(-1)/(2), (2)/(3)` are both its root.
APPEARS IN
संबंधित प्रश्न
Find the value of the discriminant in the following quadratic equation:
2x2 - 3x + 1 = O
Determine the nature of the roots of the following quadratic equation :
(x - 1)(2x - 7) = 0
Solve the following quadratic equation using formula method only
16x2 - 24x = 1
For what values of k, the roots of the equation x2 + 4x +k = 0 are real?
If one root of the equation 2x² – px + 4 = 0 is 2, find the other root. Also find the value of p.
Solve for x : `9^(x + 2) -6.3^(x + 1) + 1 = 0`.
Determine whether the given quadratic equations have equal roots and if so, find the roots:
`(4)/(3)x^2 - 2x + (3)/(4) = 0`
Without solving the following quadratic equation, find the value of ‘p’ for which the given equations have real and equal roots: x2 + (p – 3)x + p = 0.
Every quadratic equations has at most two roots.
Solve the equation: 3x2 – 8x – 1 = 0 for x.
