Advertisements
Advertisements
प्रश्न
Determine the nature of the roots of the following quadratic equation :
(x - 1)(2x - 7) = 0
Advertisements
उत्तर
(x - 1)(2x - 7) = 0
2x2 - 2x - 7x + 7 = o
2x2 - 9x + 7 = o
b2 - 4ac
= (-9)2 - 4(2)(7)
= 81 - 56
= 25
Since discriminant is a perfect square 1 hence the roots are real and rational.
APPEARS IN
संबंधित प्रश्न
Solve for x : ` 2x^2+6sqrt3x-60=0`
If `x = (-1)/2`, is a solution of the quadratic equation 3x2 + 2kx – 3 = 0, find the value of k.
Find the values of k for which the roots are real and equal in each of the following equation:
5x2 - 4x + 2 + k(4x2 - 2x - 1) = 0
Find the value of the discriminant in the following quadratic equation:
2x2 - 3x + 1 = O
Solve x2/3 + x1/3 - 2 = 0.
Form the quadratic equation whose roots are:
`sqrt(3) and 3sqrt(3)`
Given that one root of the quadratic equation ax2 + bx + c = 0 is three times the other, show that 3b2 – 16ac.
State whether the following quadratic equation have two distinct real roots. Justify your answer.
x(1 – x) – 2 = 0
The roots of equation (q – r)x2 + (r – p)x + (p – q) = 0 are equal.
Prove that 2q = p + r; i.e., p, q, and r are in A.P.
One root of equation 3x2 – mx + 4 = 0 is 1, the value of m is ______.
