Advertisements
Advertisements
प्रश्न
Determine the nature of the roots of the following quadratic equation :
x2 -5x+ 7= 0
Advertisements
उत्तर
x2 -5x+ 7= 0
b2 - 4ac
= (-5)2 - 4(1)(7)
= 25 - 28
= -3
Since discriminant is negative, hence the roots are imaginary.
APPEARS IN
संबंधित प्रश्न
Find the values of k for which the roots are real and equal in each of the following equation:
(2k + 1)x2 + 2(k + 3)x + (k + 5) = 0
Solve the following quadratic equation using formula method only
3x2 + 12 = 32 x
Find the value of m for which the equation (m + 4)x2 + (m + 1)x + 1 = 0 has real and equal roots.
In each of the following determine the; value of k for which the given value is a solution of the equation:
x2 + 2ax - k = 0; x = - a.
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
x2 - 4x + 1 = 0
Solve the following by reducing them to quadratic equations:
z4 - 10z2 + 9 = 0.
Discuss the nature of the roots of the following equation: `sqrt(3)x^2 - 2x - sqrt(3)` = 0
If the root of the given quadratic equation are real and equal, then find the value of ‘k’ X2 + 2X + k = 0.
Solve for x: 9x2 – 6px + (p2 – q2) = 0
Find the value(s) of 'a' for which the quadratic equation x2 – ax + 1 = 0 has real and equal roots.
