Advertisements
Advertisements
प्रश्न
Find the value of x, if cos (2x – 6) = cos2 30° – cos2 60°
Advertisements
उत्तर
cos (2x – 6) = cos2 30° – cos2 60°
cos (2x – 6) = cos2 (90° – 60°) – cos2 60°
cos (2x – 6) = sin2 60° – cos2 60°
cos (2x – 6) = 1 – 2 cos2 60°
= `1 - 2(1/2)^2`
= `1 - 1/2`
= `1/2`
cos (2x – 6) = `1/2`
cos (2x – 6) = cos 60°
(2x – 6) = 60°
2x = 66°
Hence, x = 33°
APPEARS IN
संबंधित प्रश्न
Express the trigonometric ratios sin A, sec A and tan A in terms of cot A.
Evaluate:
`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`
Use tables to find cosine of 8° 12’
Evaluate:
`sec26^@ sin64^@ + (cosec33^@)/sec57^@`
If \[\tan \theta = \frac{3}{4}\] then cos2 θ − sin2 θ =
If θ is an acute angle such that \[\tan^2 \theta = \frac{8}{7}\] then the value of \[\frac{\left( 1 + \sin \theta \right) \left( 1 - \sin \theta \right)}{\left( 1 + \cos \theta \right) \left( 1 - \cos \theta \right)}\]
The value of \[\frac{\tan 55°}{\cot 35°}\] + cot 1° cot 2° cot 3° .... cot 90°, is
In the following Figure. AD = 4 cm, BD = 3 cm and CB = 12 cm, find the cot θ.

Evaluate: `2(tan57°)/(cot33°) - (cot70°)/(tan20°) - sqrt(2) cos 45°`
In ∆ABC, cos C = `12/13` and BC = 24, then AC = ?
