Advertisements
Advertisements
प्रश्न
Find the value of x, if cos (2x – 6) = cos2 30° – cos2 60°
Advertisements
उत्तर
cos (2x – 6) = cos2 30° – cos2 60°
cos (2x – 6) = cos2 (90° – 60°) – cos2 60°
cos (2x – 6) = sin2 60° – cos2 60°
cos (2x – 6) = 1 – 2 cos2 60°
= `1 - 2(1/2)^2`
= `1 - 1/2`
= `1/2`
cos (2x – 6) = `1/2`
cos (2x – 6) = cos 60°
(2x – 6) = 60°
2x = 66°
Hence, x = 33°
संबंधित प्रश्न
What is the value of (cos2 67° – sin2 23°)?
Evaluate.
`(cos^2 32^@+cos^2 58^@)/(sin^2 59^@+sin^2 31^@)`
Evaluate.
`(sin77^@/cos13^@)^2+(cos77^@/sin13^@)-2cos^2 45^@`
Evaluate:
`sin80^circ/(cos10^circ) + sin59^circ sec31^circ`
Find the value of x, if sin 2x = 2 sin 45° cos 45°
Use trigonometrical tables to find tangent of 37°
Use tables to find the acute angle θ, if the value of sin θ is 0.4848
Use tables to find the acute angle θ, if the value of cos θ is 0.9848
If \[\frac{x {cosec}^2 30°\sec^2 45°}{8 \cos^2 45° \sin^2 60°} = \tan^2 60° - \tan^2 30°\]
If sin θ + sin² θ = 1 then cos² θ + cos4 θ is equal ______.
