Advertisements
Advertisements
प्रश्न
Find the value of the polynomial 5x – 4x2 + 3 at x = –1.
Advertisements
उत्तर
p(x) = 5x – 4x2 + 3
x = –1
p(–1) = 5(–1) – 4(–1)2 + 3
= –5 – 4 + 3
= -9 + 3
= –6
Thus, the value of 5x – 4x2 + 3 at x = –1 is –6.
APPEARS IN
संबंधित प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(t) = 2 + t + 2t2 – t3
Verify whether the following zeroes of the polynomial, indicated against them.
`p(x) = 3x + 1, x = -1/3`
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = x2 – 1, x = 1, –1
If `x = −1/2` is a zero of the polynomial `p(x)=8x^3-ax^2 -+2` find the value of a.
Find the number of zeros of the following polynomial represented by their graph

If p(x) = x + 3, then p(x) + p(–x) is equal to ______.
One of the zeroes of the polynomial 2x2 + 7x – 4 is ______.
`(-4)/5` is a zero of 4 – 5y
–3 is a zero of y2 + y – 6
Find the zeroes of the polynomial in the following:
h(y) = 2y
