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प्रश्न
Find the radian measure corresponding to the following degree measure:
– 47° 30'
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उत्तर
– 47° 30′
60' = 1° Then 30' = `(30/60)^circ = (1/2)^circ`
– 47° 30′ = - `(47 1/2)^circ = (-95/2)^circ`
Now
180' = π radian
`-95/2` degree = `pi/180 xx (-95/2)` radian = `((-19)/(36xx2)) pi` radian = `(-19)/72 pi` radian
∴ -47° 30' = `-19/72pi` radian
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