Advertisements
Advertisements
प्रश्न
Find the principal value of the following:
`sin^(-1) (-1/2)`
बेरीज
Advertisements
उत्तर
Let `sin^(-1) (-1/2)` = y
Then, sin y = `-1/2`
= `-sin(pi/6)`
= `sin(-pi/6)`
We know that the range of the principal value branch of sin−1 is
`[-pi/2, pi/2]` and `sin (-pi/6) = -1/2,`
Where `-pi/6 ∈ [-pi/2, pi/2]`
Therefore, the principal value of `sin^(-1) (-1/2)` is `-pi/6`.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
