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प्रश्न
Find the principal value of the following:
`cos^(-1) (sqrt3/2)`
बेरीज
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उत्तर
Let `cos^(-1) (sqrt3/2) = y`
Then, `cos y = sqrt3/2 = cos (pi/6)`
We know that the range of the principal value branch of cos−1 is
[0, π] and `cos (pi/6) = sqrt3/2`
Therefore, the principal value of `cos^(-1) (sqrt3/2)` is `pi/6`.
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