Advertisements
Advertisements
प्रश्न
Find the height of an equilateral triangle having side 2a.
Advertisements
उत्तर
Since, ABC is an equilateral triangle, AD is the perpendicular bisector of BC.
According to Pythagoras theorem,
In ∆ABD,
AB2 = AD2 + BD2
∴ (2a)2 = AD2 + a2
∴ 4a2 − a2 = AD2
∴ AD2 = 3a2
∴ AD = `sqrt3`a
Hence, the height of an equilateral triangle is `sqrt3`a
संबंधित प्रश्न
Adjacent sides of a parallelogram are 11 cm and 17 cm. If the length of one of its diagonal is 26 cm, find the length of the other.
Out of the following, which is the Pythagorean triplet?
Some question and their alternative answer are given.
In a right-angled triangle, if sum of the squares of the sides making right angle is 169 then what is the length of the hypotenuse?
Do sides 7 cm, 24 cm, 25 cm form a right angled triangle ? Give reason
A side of an isosceles right angled triangle is x. Find its hypotenuse.
In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS and ST.
In ∆ABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, Find AP.
Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.
Sum of the squares of adjacent sides of a parallelogram is 130 sq.cm and length of one of its diagonals is 14 cm. Find the length of the other diagonal.
If hypotenuse of a right angled triangle is 5 cm, find the radius of
the circle passing through all vertices of the triangle.
Choose the correct alternative:
Out of the following which is a Pythagorean triplet?
In ΔPQR, seg PM is a median, PM = 9 and PQ2 + PR2 = 290. Find the length of QR.
In ΔPQR, seg PM is the median. If PM = 9, PQ2 + PR2 = 290, Find QR.
In ΔABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, then find the length of AP.
Out of given triplets, which is not a Pythagoras triplet?
Height and base of a right angled triangle are 24 cm and 18 cm. Find the length of its hypotenuse?
Which of the following figure is formed by joining the mid-points of the adjacent sides of a square?
In the given figure, triangle ABC is a right-angled at B. D is the mid-point of side BC. Prove that AC2 = 4AD2 – 3AB2.
