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Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3i^+2j^-2k^. - Mathematics

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प्रश्न

Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector `3hati+2hatj-2hatk`.

बेरीज
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उत्तर

`3hati + 2hatj - 2hatk`

The given line passes through point A(1, 2, 3) and is parallel to the vector `vecb = 3hati + 2hatj - 2hatk`.

Position vector of point A `vec(r_1) = hati + 2hatj - 3hatk`

∴ Vector equation of a given line `vecr = vec(r_1) + λ vecb`

Or `vecr = (hati + 2hatj + 3hatk) + λ(3hati + 2hatj - 2hatk)` where λ is a scalar.

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पाठ 11: Three Dimensional Geometry - Exercise 11.1 [पृष्ठ ४७७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 11 Three Dimensional Geometry
Exercise 11.1 | Q 4 | पृष्ठ ४७७

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