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Find the distance of the point (–1, 1) from the line 12(x + 6) = 5(y – 2). - Mathematics

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प्रश्न

Find the distance of the point (–1, 1) from the line 12(x + 6) = 5(y – 2).

बेरीज
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उत्तर

12(x + 6) = 5(y – 2)

or 12x + 72 = 5y – 10

12x – 5y + 82 = 0

Distance of point  (x1, y1) from the line ax + by + c = 0 `(("ax"_1 + "by"_1 + "c"))/sqrt("a"^2 + "b"^2)`

∴ Distance from point (−1, 1) to line 12x − 5y + 8 = 0

d = `(|12 xx (-1) - 5 xx 1 + 8|)/sqrt(12^2 + 5^2)`

= `|(12 - 5 + 82)/(sqrt(144 + 25))|`

= `65/13`

= 5 Units

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पाठ 9: Straight Lines - EXERCISE 9.3 [पृष्ठ १६७]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 9 Straight Lines
EXERCISE 9.3 | Q 3. | पृष्ठ १६७

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