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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Find the area of the region bounded by the following curves, the X-axis, and the given lines: y = 6x+4,x=0,x=2

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प्रश्न

Find the area of the region bounded by the following curves, the X-axis, and the given lines:

y = `sqrt(6x + 4), x = 0, x = 2`

बेरीज
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उत्तर

Let A be the required area.

∴ A = `int_0^2 y  dx`

A = `int_0^2 sqrt(6x + 4)  dx`

= `int_0^2 (6x + 4)^(1/2)  dx`

A = `[(6x + 4)^{1/2 + 1}/((1/2 + 1) xx 6)]_0^2`

= `[(6x + 4)^{3/2}/(3/2 xx 6)]_0^2`

= `[((6x + 4)^{3/2})/9]_0^2`

= `1/9[(6x + 4)^{3/2}]_0^2`

= `1/9[(6 xx 2 + 4)^{3/2} - (6 xx 0 + 4)^{3/2}]`

= `1/9[(12 + 4)^{3/2} - (4)^{3/2}]`

= `1/9[(16)^{3/2} - (4)^{3/2}]`

= `1/9[(4^2)^{3/2} - (2^2)^{3/2}]`

∴ A = `1/9[4^3 - 2^3]`

= `1/9(64 - 8)`

= `1/9 xx 56`

= `56/9` sq.units.

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पाठ 7: Applications of Definite Integration - Exercise 7.1 [पृष्ठ १५७]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 7 Applications of Definite Integration
Exercise 7.1 | Q 1.2 | पृष्ठ १५७

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