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Find the approximate values of (4.01)3

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प्रश्न

Find the approximate values of (4.01)3 

बेरीज
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उत्तर

Let f(x) = x3

Then, f'(x) = 3x2

Take a = 4 and h = 0.01

Then f(a) = f(4) = 43 = 64

and f'(a) = f'(4) = 3 × 42 = 48

The formula for approximation is

f(a + h) ≑ f(a) + h.f'(a)

∴ (4.01)3 = f(4 + 0.01)

≑ f(4) + (0.01) f'(4)

≑ 64 + 0.01 × 48

≑ 64 + 0.48

= 64.48

∴ (4.01)3 ≑ 64.48

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पाठ 2: Applications of Derivatives - Exercise 2.2 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 2 Applications of Derivatives
Exercise 2.2 | Q 1.5 | पृष्ठ ७५

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