Advertisements
Advertisements
प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x+1.
Advertisements
उत्तर १
Let p(x) = x3 + 3x2 + 3x + 1
x+1 = 0 ⇒ x = -1
∴ Remainder = p(-1) = (-1)3 + 3(-1)2 + 3(-1) + 1
= -1 + 3 - 3 + 1
= 0
Therefore, the remainder is 0.
उत्तर २
By long division,
Therefore, the remainder is 0.
संबंधित प्रश्न
Using the Remainder and Factor Theorem, factorise the following polynomial:
`x^3 + 10x^2 - 37x + 26`
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 19x + 6
If x3 + ax2 + bx + 6 has x – 2 as a factor and leaves a remainder 3 when divided by x – 3, find the values of a and b.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(2x3 − 2x2 + ax − a) ; (x − a)
Polynomials bx2 + x + 5 and bx3 − 2x + 5 are divided by polynomial x - 3 and the remainders are m and n respectively. If m − n = 0 then find the value of b.
Find without division, the remainder in the following :
x3 + 8x2 + 7x- 11 is divisible by (x+4)
Using remainder theorem, find the remainder on dividing f(x) by (x + 3) where f(x) = 3x3 + 7x2 – 5x + 1
When 2x3 – x2 – 3x + 5 is divided by 2x + 1, then the remainder is
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 3x2 + 4x + 50; g(x) = x – 3
Determine which of the following polynomials has x – 2 a factor:
4x2 + x – 2
