Advertisements
Advertisements
प्रश्न
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 3x2 + 4x + 50; g(x) = x – 3
Advertisements
उत्तर
p(x) = x3 – 3x2 + 4x + 50, g(x) = x – 3
Let g(x) = x – 3
x – 3 = 0
x = 3
p(3) = 33 – 3(32) + 4(3) + 50
= 27 – 27 + 12 + 50
= 62
∴ Remainder = 62.
APPEARS IN
संबंधित प्रश्न
Use Remainder theorem to factorize the following polynomial:
`2x^3 + 3x^2 - 9x - 10`
Find the value of a, if the division of ax3 + 9x2 + 4x – 10 by x + 3 leaves a remainder 5.
The polynomials 2x3 – 7x2 + ax – 6 and x3 – 8x2 + (2a + 1)x – 16 leaves the same remainder when divided by x – 2. Find the value of ‘a’.
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3) x – 6 leave the same remainder. Find the value of ‘p’.
Find without division, the remainder in the following:
5x3 - 7x2 +3 is divided by (x-1)
Find without division, the remainder in the following:
2x3 - 3x2 + 6x - 4 is divisible by (2x-3)
A polynomial f(x) when divided by (x - 1) leaves a remainder 3 and when divided by (x - 2) leaves a remainder of 1. Show that when its divided by (x - i)(x - 2), the remainder is (-2x + 5).
If (x – 2) is a factor of the expression 2x3 + ax2 + bx – 14 and when the expression is divided by (x – 3), it leaves a remainder 52, find the values of a and b.
Check whether p(x) is a multiple of g(x) or not
p(x) = x3 – 5x2 + 4x – 3, g(x) = x – 2
4x2 – kx + 5 leaves a remainder 2 when divided by x – 1. The value of k is ______.
