Advertisements
Advertisements
प्रश्न
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by x + 3
Advertisements
उत्तर
f(x) = 2x3 – 3x2 + 4x + 7
Let x + 3 = 0, then x = – 3
Substituting the value of x in f(x)
f(–3) = 2(–3)3 – 3(–3)2 + 4(–3) + 7
= 2 x (–27) – 3(9) + 4(–3) + 7
= –54 – 27 – 12 + 7
= – 93 + 7
= – 86
∴ Remainder = – 86.
APPEARS IN
संबंधित प्रश्न
What number should be added to 3x3 – 5x2 + 6x so that when resulting polynomial is divided by x – 3, the remainder is 8?
Find the value of ‘m’, if mx3 + 2x2 – 3 and x2 – mx + 4 leave the same remainder when each is divided by x – 2.
Using the remainder theorem, find the remainders obtained when x3 + (kx + 8 )x + k is divided by x + 1 and x − 2.
Hence, find k if the sum of the two remainders is 1.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(x2 − 7x + 9) ; (x + 1)
Find the values of a and b when the polynomials f(x)= 2x2 -5x +a and g(x)= 2x2 + 5x +b both have a factor (2x+1).
Use remainder theorem and find the remainder when the polynomial g(x) = x3 + x2 – 2x + 1 is divided by x – 3.
When x3 + 3x2 – kx + 4 is divided by (x – 2), the remainder is k. Find the value of k.
If x + 1 is a factor of 3x3 + kx2 + 7x + 4, then the value of k is
If x3 + 6x2 + kx + 6 is exactly divisible by (x + 2), then k = ?
By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial: x4 + 1; x – 1
