मराठी

Find the Principal and General Solutions of the Equation `Tan X = Sqrt3` - Mathematics

Advertisements
Advertisements

प्रश्न

Find the principal and general solutions of the equation `tan x = sqrt3`

Advertisements

उत्तर

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometric Functions - Exercise 3.4 [पृष्ठ ७८]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 3 Trigonometric Functions
Exercise 3.4 | Q 1 | पृष्ठ ७८

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the principal and general solutions of the equation sec x = 2


Find the general solution of cosec x = –2


Find the general solution for each of the following equations sec2 2x = 1– tan 2x


Prove that: tan (−225°) cot (−405°) −tan (−765°) cot (675°) = 0


Prove that

\[\frac{cosec(90^\circ + x) + \cot(450^\circ + x)}{cosec(90^\circ - x) + \tan(180^\circ - x)} + \frac{\tan(180^\circ + x) + \sec(180^\circ - x)}{\tan(360^\circ + x) - \sec( - x)} = 2\]

 


Prove that:
\[\sin^2 \frac{\pi}{18} + \sin^2 \frac{\pi}{9} + \sin^2 \frac{7\pi}{18} + \sin^2 \frac{4\pi}{9} = 2\]

 

Prove that:
\[\sec\left( \frac{3\pi}{2} - x \right)\sec\left( x - \frac{5\pi}{2} \right) + \tan\left( \frac{5\pi}{2} + x \right)\tan\left( x - \frac{3\pi}{2} \right) = - 1 .\]


Prove that:
\[\sin\frac{13\pi}{3}\sin\frac{8\pi}{3} + \cos\frac{2\pi}{3}\sin\frac{5\pi}{6} = \frac{1}{2}\]


If tan x = \[x - \frac{1}{4x}\], then sec x − tan x is equal to


If \[f\left( x \right) = \cos^2 x + \sec^2 x\], then


Which of the following is incorrect?


Which of the following is correct?


Find the general solution of the following equation:

\[\sin x = \frac{1}{2}\]

Find the general solution of the following equation:

\[\sec x = \sqrt{2}\]

Find the general solution of the following equation:

\[\tan x = - \frac{1}{\sqrt{3}}\]

Find the general solution of the following equation:

\[\tan mx + \cot nx = 0\]

Find the general solution of the following equation:

\[\tan px = \cot qx\]

 


Solve the following equation:

\[4 \sin^2 x - 8 \cos x + 1 = 0\]

Solve the following equation:

\[3 \cos^2 x - 2\sqrt{3} \sin x \cos x - 3 \sin^2 x = 0\]

Solve the following equation:

\[\cos 4 x = \cos 2 x\]

Solve the following equation:

\[\cos x + \sin x = \cos 2x + \sin 2x\]

Solve the following equation:

\[\sin 3x - \sin x = 4 \cos^2 x - 2\]

Solve the following equation:

\[\sin 2x - \sin 4x + \sin 6x = 0\]

Solve the following equation:

\[\tan 3x + \tan x = 2\tan 2x\]

Solve the following equation:

\[\sin x + \cos x = 1\]

Solve the following equation:
\[\cot x + \tan x = 2\]

 


Solve the following equation:
\[5 \cos^2 x + 7 \sin^2 x - 6 = 0\]


Solve the following equation:
4sinx cosx + 2 sin x + 2 cosx + 1 = 0 


If cos x = k has exactly one solution in [0, 2π], then write the values(s) of k.

 

If \[3\tan\left( x - 15^\circ \right) = \tan\left( x + 15^\circ \right)\] \[0 < x < 90^\circ\], find θ.


If a is any real number, the number of roots of \[\cot x - \tan x = a\] in the first quadrant is (are).


If \[\cot x - \tan x = \sec x\], then, x is equal to

 


A value of x satisfying \[\cos x + \sqrt{3} \sin x = 2\] is

 

Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

2 sin2x + 1 = 3 sin x


Solve the following equations:
sin 2θ – cos 2θ – sin θ + cos θ = θ


Solve the following equations:
`sin theta + sqrt(3) cos theta` = 1


Solve the following equations:
2cos 2x – 7 cos x + 3 = 0


If 2sin2θ = 3cosθ, where 0 ≤ θ ≤ 2π, then find the value of θ.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×