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Solve the following equations:cos θ + cos 3θ = 2 cos 2θ

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प्रश्न

Solve the following equations:
cos θ + cos 3θ = 2 cos 2θ

बेरीज
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उत्तर

cos 3θ + cos θ = 2 cos 2θ

`2 cos ((3theta + theta)/2) * cos ((3theta - theta)/2)` = 2 cos 2θ

`2cos ((4theta)/2) * cos ((2theta)/2)` = 2 cos 2θ 

2 cos 2θ . cos θ = 2 cos 2θ

cos 2θ . cos θ – cos 2θ = θ

cos 2θ (cos θ – 1) = θ

cos 2θ = θ or cos θ – 1 = θ

cos 2θ = θ or cos θ = 1

To find the general solution of cos 2θ = θ

The general solution is

2θ = `(2"n" + 1) pi/2`, n ∈ Z

θ = `(2"n" + 1) pi/4`, n ∈ Z

To find the general solution of cos θ = 1

cos θ = 1

cos θ = cos 0

The general solution is θ = 2nπ , n ∈ Z

∴ The required solutions are

θ = `(2"n" + 1) pi/4`, n ∈ Z

or

θ = 2nπ, n ∈ Z

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पाठ 3: Trigonometry - Exercise 3.8 [पृष्ठ १३३]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.8 | Q 3. (iii) | पृष्ठ १३३

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