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Find the Inverse Relation R−1 in Each of the Cases:(I) R = {(1, 2), (1, 3), (2, 3), (3, 2), (5, 6)} - Mathematics

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प्रश्न

Find the inverse relation R−1 in each of the cases:

(i) R = {(1, 2), (1, 3), (2, 3), (3, 2), (5, 6)}

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उत्तर

(i) R = {(1, 2), (1, 3), (2, 3), (3, 2), (5, 6)}
R−1 = {(2, 1), (3, 1), (3, 2), (2, 3), (6, 5)}


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पाठ 2: Relations - Exercise 2.3 [पृष्ठ २०]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 2 Relations
Exercise 2.3 | Q 4.1 | पृष्ठ २०

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संबंधित प्रश्‍न

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Write the relation R = {(x, x3): x is a prime number less than 10} in roster form.


Let A = {1, 2, 3, 4}, B = {1, 5, 9, 11, 15, 16} and f = {(1, 5), (2, 9), (3, 1), (4, 5), (2, 11)}. Is the following true?

f is a relation from A to B

Justify your answer in case.


If A = [1, 2, 3], B = [4, 5, 6], which of the following are relations from A to B? Give reasons in support of your answer.

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(ii) [(1, 5), (2, 6), (3, 4), (3, 6)]
(iii) [(4, 2), (4, 3), (5, 1)]
(iv) A × B.


Find the inverse relation R−1 in each of the cases:

(iii) R is a relation from {11, 12, 13} to (8, 10, 12] defined by y = x − 3.

 

Let A = (3, 5) and B = (7, 11). Let R = {(ab) : a ∈ A, b ∈ B, a − b is odd}. Show that R is an empty relation from A into B.


Determine the domain and range of the relation R defined by

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Let R be a relation from N to N defined by R = {(a, b) : a, b ∈ N and a = b2}. Is the statement true?

(a, b) ∈ R implies (b, a) ∈ R

Justify your answer in case.


For the relation R1 defined on R by the rule (ab) ∈ R1 ⇔ 1 + ab > 0. Prove that: (ab) ∈ R1 and (b , c) ∈ R1 ⇒ (ac) ∈ R1 is not true for all abc ∈ R.


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Let A = {6, 8} and B = {1, 3, 5}
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h = {(4, 6), (3, 9), (– 11, 6), (3, 11)}


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