Question

Figure A particle starts from a point A and travels along the solid curve shown in the following figure. Find approximately the position B of the particle such that the average velocity between the position A and B has the same direction as the instantaneous velocity at B.

 

Answer 1

At position B , the instantaneous velocity of the particle has the direction along \[\vec{BC}\] .

Average velocity between A and B,

 

\[V_{av} = \frac{\text{ Displacement} }{\text{ Time } }\]

\[= \left( \frac{\vec{AB}}{t} \right)\]

We can see that  \[\vec{AB}\] and \[\vec{BC}\]  are in the same direction. The point is B (5 m, 3 m).