Advertisements
Advertisements
प्रश्न
Factorize: x3 + x - 3x2 - 3
Advertisements
उत्तर
x3 + x - 3x2 - 3
Taking x common in (x3 + x)
= x (x2 +1) - 3x2 - 3
Taking -3 common in (-3x2 - 3)
= x(x2 +1) - 3(x2 +1)
Now, we take (x2 +1) common
= (x2 +1)( x - 3)
`∴ x^3 + x - 3x^2 - 3 = (x^2 + 1)(x - 3)`
APPEARS IN
संबंधित प्रश्न
Factorize 64a3 +125b3 + 240a2b + 300ab2
Factorize 8x3 + 27 y3 + 36x2 y + 54xy2
If \[x^2 + \frac{1}{x^2} = 18,\] find the values of \[x + \frac{1}{x} \text { and } x - \frac{1}{x} .\]
The factors of 8a3 + b3 − 6ab + 1 are
Separate the constants and variables from the following :
`-7,7+"x",7"x"+"yz",sqrt5,sqrt("xy"),(3"yz")/8,4.5"y"-3"x",`
8 −5, 8 − 5x, 8x −5y × p and 3y2z ÷ 4x
Evaluate: - 4y (15 + 12y - 8z) (x - 2y)
Evaluate: (a2 + b2 + c2 - ab - bc - ca)(a + b + c)
Divide: 4a2 + 4a + 1 by 2a + 1
Divide: m3 − 4m2 + m + 6 by m2 − m − 2
Write in the form of an algebraic expression:
Perimeter (P) of a rectangle is two times the sum of its length (l) and its breadth (b).
