Advertisements
Advertisements
प्रश्न
Factorize `[x^2 + 1/x^2] - 4[x + 1/x] + 6`
Advertisements
उत्तर
`= x^2 + 1/x^2 - 4x - 4/x + 4 + 2`
`= x^2 + 1/x^2 + 4 + 2 - 4/x - 4x`
`= (x^2) + (1/x)^2 + (-2)^2 + 2 xx x xx x 1/x + 2x 1/x xx (-2) + 2(-2)x`
Using identity
a2 + b2 + c2 + 2ab + 2bc + 2ca = (a + b + c)2
We get
`= [x + 1/x + (-2)]^2`
`= [x + 1/x - 2]^2`
`= [x + 1/x - 2][x + 1/x - 2]`
`∴ [x^2 + 1/x^2] - 4[x + 1/x] + 6 = [x + 1/x - 2][x + 1/x - 2]`
APPEARS IN
संबंधित प्रश्न
Factorize the following expressions:
10x4y – 10xy4
Factorize the following expressions:
1029 – 3x3
(2x - 3y)3 + (4z - 2x)3 + (3y - 4z )3
If x − y = 7 and xy = 9, find the value of x2 + y2
Write the value of 253 − 753 + 503.
Evaluate: (a2 + b2 + c2 - ab - bc - ca)(a + b + c)
Write in the form of an algebraic expression:
Surface area of a cube is six times the square of its edge.
Give an algebraic equation for the following statement:
“The difference between the area and perimeter of a rectangle is 20”.
–b – 0 is equal to ______.
In the term 10xyz, what is the numerical coefficient?
