Advertisements
Advertisements
प्रश्न
Factorize: a (a + b)3 - 3a2b (a + b)
Advertisements
उत्तर
Taking (a + b) common in two terms
= (a + b){a (a + b)2 - 3a2b}
Now, using (a + b)2 = a2 + b2 + 2ab
= (a + b){a (a2 + b2 + 2ab) - 3a2b}
= (a + b){a3 + ab2 + 2a2b - 3a2b}
= (a + b){a3 + ab2 - a2b}
= (a + b) a{a2 + b2 - ab}
= a (a + b)(a2 + b2 - ab)
∴ a (a + b)3 - 3a2b (a + b) = a (a + b)(a2 + b2 - ab)
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operation.
Subtraction of z from y
Factorize the following expressions:
10x4y – 10xy4
Factorize 125x3 - 27 y3 - 225x2 y +135xy2
Factorize : x2 − 1 − 2a − a2
The expression (a − b)3 + (b − c)3 + (c −a)3 can be factorized as
The value of \[\frac{(2 . 3 )^3 - 0 . 027}{(2 . 3 )^2 + 0 . 69 + 0 . 09}\]
Divide: - 16ab2c by 6abc
Divide: 2a2 - 11a + 12 by a - 4
Divide: 5x2 - 3x by x
Rohan’s mother gave him ₹ 3xy2 and his father gave him ₹ 5(xy2 + 2). Out of this total money he spent ₹ (10 – 3xy2) on his birthday party. How much money is left with him?
