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प्रश्न
Factorise the following using appropriate identity:
4y2 – 4y + 1
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उत्तर
4y2 – 4y + 1
= (2y)2 – 2(2y)(1) + (1)2
= (2y – 1)2 ...[x2 – 2xy + y2 = (x – y)2]
= (2y – 1)(2y – 1)
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