Advertisements
Advertisements
प्रश्न
If `"a" + 1/"a" = 6;`find `"a"^2 - 1/"a"^2`
बेरीज
Advertisements
उत्तर
`"a"^2 - 1/"a"^2`
= `("a" + 1/"a")("a" - 1/"a")`
= (6)`(±4sqrt(2))`
= ±24`sqrt(2)`.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Expand the following, using suitable identity:
(–2x + 3y + 2z)2
Verify that `x^3+y^3+z^3-3xyz=1/2(x+y+z)[(x-y)^2+(y-z)^2+(z-x)^2]`
Simplify the following products:
`(x^3 - 3x^2 - x)(x^2 - 3x + 1)`
Find the value of 4x2 + y2 + 25z2 + 4xy − 10yz − 20zx when x = 4, y = 3 and z = 2.
If \[x - \frac{1}{x} = 5\], find the value of \[x^3 - \frac{1}{x^3}\]
If \[x^2 + \frac{1}{x^2} = 98\] ,find the value of \[x^3 + \frac{1}{x^3}\]
If \[x^2 + \frac{1}{x^2} = 102\], then \[x - \frac{1}{x}\] =
If \[\frac{a}{b} + \frac{b}{a} = 1\] then a3 + b3 =
If `x + (1)/x = 3`; find `x^2 + (1)/x^2`
If `"r" - (1)/"r" = 4`; find : `"r"^4 + (1)/"r"^4`
