Advertisements
Advertisements
प्रश्न
Factorise the following using appropriate identity:
4y2 – 4y + 1
Advertisements
उत्तर
4y2 – 4y + 1
= (2y)2 – 2(2y)(1) + (1)2
= (2y – 1)2 ...[x2 – 2xy + y2 = (x – y)2]
= (2y – 1)(2y – 1)
APPEARS IN
संबंधित प्रश्न
Verify that `x^3+y^3+z^3-3xyz=1/2(x+y+z)[(x-y)^2+(y-z)^2+(z-x)^2]`
Write in the expanded form (a2 + b2 + c2 )2
Evaluate of the following:
(99)3
If x = −2 and y = 1, by using an identity find the value of the following
If \[x + \frac{1}{x} = 3\] then \[x^6 + \frac{1}{x^6}\] =
If \[x^3 + \frac{1}{x^3} = 110\], then \[x + \frac{1}{x} =\]
If a − b = −8 and ab = −12, then a3 − b3 =
Find the square of : 3a - 4b
If a - b = 4 and a + b = 6; find
(i) a2 + b2
(ii) ab
If a - `1/a`= 8 and a ≠ 0 find :
(i) `a + 1/a (ii) a^2 - 1/a^2`
Use the direct method to evaluate :
(2a+3) (2a−3)
Expand the following:
(2p - 3q)2
Expand the following:
(x - 3y - 2z)2
Evaluate the following without multiplying:
(95)2
Evaluate, using (a + b)(a - b)= a2 - b2.
4.9 x 5.1
Evaluate, using (a + b)(a - b)= a2 - b2.
15.9 x 16.1
Simplify:
`("a" - 1/"a")^2 + ("a" + 1/"a")^2`
Simplify:
(3a + 2b - c)(9a2 + 4b2 + c2 - 6ab + 2bc +3ca)
Expand the following:
`(4 - 1/(3x))^3`
Find the value of x3 + y3 – 12xy + 64, when x + y = – 4
